x^2=26y

Lösung

x^{2} = 26 y

(h, k) = (0, 0), p = \frac{13}{2}

Schritte zur Lösung

x^{2} = 26 y

Rewrite

x^{2} = 26 y

in the standard form:

4 \cdot \frac{13}{2} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{13}{2}

(x - 3)^{2} = 12 (y - 4)

y^{2} \leq x

3 x^{2} - 6 x + 4 - y = 0

x = - y^{2} + 8 y - 14

x^{2} + 8 s + 25 = 0