solvefor m,x(x+17)<60m(x)^2

解答

求解

m, x (x + 17) < 60 m (x)^{2}

m > \frac{x + 17}{60 x}; x < 0 or x > 0

求解步骤

x (x + 17) < 60 m x^{2}

交换两边

60 m x^{2} > x (x + 17)

两边除以

60 x^{2}; x < 0 or x > 0

m > \frac{x + 17}{60 x}; x < 0 or x > 0

x^{2} - 4 y^{2} + 2 x + 11 y - 7 = 0

\frac{y ^{2}}{25} - \frac{x ^{2}}{24} = 1

x^{2} - y^{2} - 2 x = 0

- 9 x^{2} + 25 y^{2} - 54 x - 50 y - 281 = 0

\frac{x ^{2}}{64} - \frac{y ^{2}}{- 39} = 1