foki 3x^2-2y^2=1

Lösung

foki

3 x^{2} - 2 y^{2} = 1

(\frac{5}{6}, 0), (- \frac{5}{6}, 0)

Schritte zur Lösung

(h + c, k), (h - c, k)

Calculate Hyperbola properties

3 x^{2} - 2 y^{2} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = \frac{1}{3}, b = \frac{1}{2}

(0 + c, 0), (0 - c, 0)

Compute

c :

c = \frac{1}{3}^{2} + \frac{1}{2}^{2} : \frac{5}{6}

(0 + \frac{5}{6}, 0), (0 - \frac{5}{6}, 0)

Fasse zusammen

(\frac{5}{6}, 0), (- \frac{5}{6}, 0)

f oc i \frac{y ^{2}}{25} - \frac{x ^{2}}{25} = 1

f oc i \frac{( x - 6 ) ^{2}}{10} - \frac{( y + 2 ) ^{2}}{17} = 1

f oc i \frac{( x - 1 ) ^{2}}{1 2 ^{2}} - \frac{( y - 11 ) ^{2}}{8 ^{2}} = 1

f oc i \frac{( x + 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{12} = 1

f oc i \frac{( y - 3 ) ^{2}}{7} - \frac{( x + 6 ) ^{2}}{42} = 1