f(x)=-2x^2+2f(x)ind(-6)

Lösung

f (x) = - 2 x^{2} + 2 f (x) in d (- 6)

(h, k) = (0, 0), p = \frac{- 1 - 12 d in}{8}

Schritte zur Lösung

y = - 2 x^{2} + 2 y in d (- 6)

Rewrite

y = - 2 x^{2} + 2 y in d (- 6)

in the standard form:

4 \cdot \frac{- 1 - 12 d in}{8} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{- 1 - 12 d in}{8}

4 x^{2} + 7 x + 12 k (x) - 3 = 0

4 x - 2 x^{2} + y = 6

x^{2} = \frac{1}{2} y

x = y^{2} + 2 y + 4

x = y^{2} + 2 y + 2