exzentrizität (y^2)/(25)-(x^2)/(16)=1

Lösung

exzentrizität

\frac{y ^{2}}{25} - \frac{x ^{2}}{16} = 1

\frac{41}{5}

Dezimale

1.28062 \dots

Schritte zur Lösung

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

\frac{y ^{2}}{25} - \frac{x ^{2}}{16} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 4

= \frac{5 ^{2} + 4 ^{2}}{5}

Fasse zusammen

= \frac{41}{5}

ecce n t r i c i t y \frac{( x + 1 ) ^{2}}{4} - (y - 5)^{2} = 4

ecce n t r i c i t y 9 x^{2} - 16 y^{2} = 144

ecce n t r i c i t y \frac{x ^{2}}{100} - \frac{y ^{2}}{64} = 1

ecce n t r i c i t y 9 y^{2} - 49 x^{2} = 441

ecce n t r i c i t y 9 x^{2} - 18 x - 16 y^{2} - 64 y = 199