y^2-3y+5x+2=0

Lösung

y^{2} - 3 y + 5 x + 2 = 0

(h, k) = (\frac{1}{20}, \frac{3}{2}), p = - \frac{5}{4}

Schritte zur Lösung

y^{2} - 3 y + 5 x + 2 = 0

Rewrite

y^{2} - 3 y + 5 x + 2 = 0

in the standard form

4 (- \frac{5}{4}) (x - \frac{1}{20}) = (y - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{20}, \frac{3}{2}), p = - \frac{5}{4}

(x - 3)^{2} = - 4 (y - 5)

x^{2} = - 12 (y - 3)

x + y^{2} = 10

x + y^{2} = 12

2 x + y^{2} = 0