leitkurve y^2=12x

Lösung

leitkurve

y^{2} = 12 x

x = - 3

Schritte zur Lösung

Rewrite

y^{2} = 12 x

in the standard form:

4 \cdot 3 (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = 3

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - 3

Fasse zusammen

x = - 3

f oc i \frac{y ^{2}}{16} - \frac{x ^{2}}{9} = 1

x^{2} + y^{2} + 4 y = 0

a x i s \frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

a sy m pt o t es \frac{x ^{2}}{25} - \frac{y ^{2}}{9} = 1

x^{2} + y^{2} = 2