f(x)=2x^2+2x-2sif(-2)

Lösung

f (x) = 2 x^{2} + 2 x - 2 s i f (- 2)

(h, k) = (- \frac{- f + 2}{4}, - \frac{i}{2 f} \cdot \frac{( - f + 2 ) ^{2}}{16}), p = - \frac{i f}{2}

Schritte zur Lösung

f x = 2 x^{2} + 2 x - 2 s i f (- 2)

Rewrite

f x = 2 x^{2} + 2 x - 2 s i f (- 2)

in the standard form

4 (- \frac{i f}{2}) (s - (- \frac{i}{2 f} \cdot \frac{( - f + 2 ) ^{2}}{16})) = (x - (- \frac{- f + 2}{4}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{- f + 2}{4}, - \frac{i}{2 f} \cdot \frac{( - f + 2 ) ^{2}}{16}), p = - \frac{i f}{2}

y^{2} = - 60 x

6 x + y^{2} = 0

y < 2 x^{2} + 3 x - 5

4 - (y - 4) 2 = (x^{2} + 6 x + 9)

x = \frac{3}{2} y^{2} - 3