0=-y-x^2+4x+5

Lösung

0 = - y - x^{2} + 4 x + 5

(h, k) = (2, 9), p = - \frac{1}{4}

Schritte zur Lösung

0 = - y - x^{2} + 4 x + 5

Rewrite

0 = - y - x^{2} + 4 x + 5

in the standard form

4 (- \frac{1}{4}) (y - 9) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 9), p = - \frac{1}{4}

x^{2} - 4 z = 0

4 \cdot a + b^{2} = 40

f (x) (f (x)) = x

2 x^{2} + 24 x - 5 y = - 57

18 y^{2} - 24 y + 36 x - 1 = 0