x^2+4x-8y+44=0

Lösung

x^{2} + 4 x - 8 y + 44 = 0

(h, k) = (- 2, 5), p = 2

Schritte zur Lösung

x^{2} + 4 x - 8 y + 44 = 0

Rewrite

x^{2} + 4 x - 8 y + 44 = 0

in the standard form

4 \cdot 2 (y - 5) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, 5), p = 2

y > 2 x^{2} + 5

- 3 x^{2} + 6 y + 2 x = 6

x^{2} + (y - 1) 2 = 1

- f (x) = 3 x^{2} - 3 x - 4

x^{2} + (y - 1) 2 = 4