(x-4)^2=-4(-5)(y+2)

解答

(x - 4)^{2} = - 4 (- 5) (y + 2)

(h, k) = (4, - 2), p = 5

求解步骤

(x - 4)^{2} = - 4 (- 5) (y + 2)

将

(x - 4)^{2} = - 4 (- 5) (y + 2)

改写为标准形式:

4 \cdot 5 (y - (- 2)) = (x - 4)^{2}

因此抛物线性质是:

(h, k) = (4, - 2), p = 5

\frac{1}{t + 5} = \frac{6}{r ^{2} - 25}

y^{2} - 8 y + 8 x + 16 = 0

25 = \frac{x}{y ^{2}}

x^{2} - 76 x + 20 y + 50 = 0

x 0.14 x - 0.03 y = 0.48