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Beliebt Geometry >

(8(8+1))/2 >= 8*q+p-(q(q-1))/2

Lösung

\frac{8 ( 8 + 1 )}{2} \geq 8 \cdot q + p - \frac{q ( q - 1 )}{2}

Lösung

(h, k) = (\frac{17}{2}, - \frac{1}{8}), p = \frac{1}{2}

Schritte zur Lösung

\frac{8 ( 8 + 1 )}{2} \geq 8 q + p - \frac{q ( q - 1 )}{2}

Rewrite

\frac{8 ( 8 + 1 )}{2} \geq 8 q + p - \frac{q ( q - 1 )}{2}

in the standard form

4 \cdot \frac{1}{2} (p - (- \frac{1}{8})) = (q - \frac{17}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{17}{2}, - \frac{1}{8}), p = \frac{1}{2}

Graph

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