(x-4)^2=12(y+1)

Lösung

(x - 4)^{2} = 12 (y + 1)

(h, k) = (4, - 1), p = 3

Schritte zur Lösung

(x - 4)^{2} = 12 (y + 1)

Rewrite

(x - 4)^{2} = 12 (y + 1)

in the standard form:

4 \cdot 3 (y - (- 1)) = (x - 4)^{2}

Therefore parabola properties are:

(h, k) = (4, - 1), p = 3

2 x^{2} - y + 7 = 0

20 x - 4 y = - 4 x^{2}

2 x^{2} - 7 y = 0

(x + 5)^{2} = 24 (y - 4)

2 x^{2} - 7 y = 9