y<=-2x^2+4x-1

Lösung

y \leq - 2 x^{2} + 4 x - 1

(h, k) = (1, 1), p = - \frac{1}{8}

Schritte zur Lösung

y \leq - 2 x^{2} + 4 x - 1

Rewrite

y \leq - 2 x^{2} + 4 x - 1

in the standard form

4 (- \frac{1}{8}) (y - 1) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, 1), p = - \frac{1}{8}

x 3 x = 20 - 4 y

- 9 x^{2} - 7 y - 3 = 0

y = 1.9 x^{2} - 3.86 x + 15.25 y

Z^{1} = 4 + J^{2}

x^{2} + 4 y = 7