x^2+6=-12y

Lösung

x^{2} + 6 = - 12 y

(h, k) = (0, - \frac{1}{2}), p = - 3

Schritte zur Lösung

x^{2} + 6 = - 12 y

Rewrite

x^{2} + 6 = - 12 y

in the standard form:

4 (- 3) (y - (- \frac{1}{2})) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{1}{2}), p = - 3

y^{2} + 16 x - 2 y - 15 = 0

3 x^{2} + 2 y = 26

3 x^{2} + 2 y = 20

x - y^{2} \geq 1

y^{2} + 4 x - 8 y = - 12