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Beliebt Geometry >

4u^2+20v=0

Lösung

4 u^{2} + 20 v = 0

Lösung

(h, k) = (0, 0), p = - \frac{5}{4}

Schritte zur Lösung

4 u^{2} + 20 v = 0

Rewrite

4 u^{2} + 20 v = 0

in the standard form:

4 (- \frac{5}{4}) (v - 0) = (u - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{5}{4}

Graph

Beliebte Beispiele

y \leq - x^{2}

5x^2+25x+10y=15

5 x^{2} + 25 x + 10 y = 15

x^{2} - 8 x - 10 y - 4 = 0

0.2x^2-0.8x-0.2=o

0.2 x^{2} - 0.8 x - 0.2 = o

q^1=105-3p^1+p^2

q^{1} = 105 - 3 p^{1} + p^{2}