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Beliebt Geometry >

leitkurve y^2+2x+6y+17=0

Lösung

leitkurve

y^{2} + 2 x + 6 y + 17 = 0

Lösung

x = - \frac{7}{2}

Schritte zur Lösung

Rewrite

y^{2} + 2 x + 6 y + 17 = 0

in the standard form

4 (- \frac{1}{2}) (x - (- 4)) = (y - (- 3))^{2}

(h, k) = (- 4, - 3), p = - \frac{1}{2}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(- 4, - 3)

x-coordinate

x = - 4 - p

x = - 4 - (- \frac{1}{2})

Fasse zusammen

x = - \frac{7}{2}

Graph

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