leitkurve 2.6+2.2x-0.6x^2

Lösung

leitkurve

2.6 + 2.2 x - 0.6 x^{2}

y = 5.03333 \dots

Schritte zur Lösung

Rewrite

y = 2.6 + 2.2 x - 0.6 x^{2}

in the standard form

4 (- 0.41666 \dots) (y - 4.61666 \dots) = (x - 1.83333 \dots)^{2}

(h, k) = (1.83333 \dots, 4.61666 \dots), p = - 0.41666 \dots

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(1.83333 \dots, 4.61666 \dots)

y-coordinate

y = 4.61666 \dots - p

y = 4.61666 \dots - (- 0.41666 \dots)

Fasse zusammen

y = 5.03333 \dots

d i rec t r i x x = (y - 2) (3 y + 3)

d i rec t r i x x^{2} - 6 x + 16

d i rec t r i x x^{2} - 6 x + 18

d i rec t r i x (x - 3)^{2} = - 12 (y - 2)

d i rec t r i x \frac{4 x ^{3} - 7 x ^{2} - 11 x + 5}{4 x + 5}