What is (4+3)-(3\times 2)+1 ?

The solution to (4+3)-(3\times 2)+1 is 2

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(4+3)-(3\times 2)+1

(4 + 3) - (3 \cdot 2) + 1

2

Solution steps

(4 + 3) - (3 \cdot 2) + 1

Follow the PEMDAS order of operations

Calculate within parentheses

(4 + 3) : 7

4 + 3

4 + 3 = 7

= 7

= 7 - (3 \cdot 2) + 1

Calculate within parentheses

(3 \cdot 2) : 6

3 \cdot 2

3 \cdot 2 = 6

= 6

= 7 - 6 + 1

Add and subtract (left to right)

7 - 6 + 1 : 2

7 - 6 + 1

7 - 6 = 1

= 1 + 1

1 + 1 = 2

= 2

= 2

- 5 - (- 5) + 5 \times 5 \div 5 + 5

800 + (20 - 3 \times 4 + 5 [18 - (6 - 1) 3 + (5 - 2) 4])

3 - 2 [8 - (3 - 2)]

(10 \times 3) \div 5

(4 + 5^{5} + 8^{9})^{0}