What is (-4)^2-4(1)(4) ?

The solution to (-4)^2-4(1)(4) is 0

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(-4)^2-4(1)(4)

(- 4)^{2} - 4 (1) (4)

0

Solution steps

(- 4)^{2} - 4 (1) (4)

Follow the PEMDAS order of operations

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= 16 - 4 (1) (4)

Multiply and divide (left to right)

4 (1) (4) : 16

4 (1) (4)

4 (1) = 4

4 (1)

Apply rule:

(a) = a

(1) = 1

= 4 \cdot 1

Multiply the numbers:

4 \cdot 1 = 4

= 4

= 4 (4)

4 (4) = 16

4 (4)

Apply rule:

(a) = a

(4) = 4

= 4 \cdot 4

Multiply the numbers:

4 \cdot 4 = 16

= 16

= 16

= 16 - 16

Add and subtract (left to right)

16 - 16 : 0

16 - 16

16 - 16 = 0

= 0

= 0

3 - 5 \times (4 - 6 \times 2 - 5 + 7) + 8 \times 3

1000 \times 5 \times \frac{2}{5} + 1 \times 0

6 \div 4 \div 5

(- 21 - 203) \div 7 + 18

(15 + 45) \div 3 - 12