What is (4)^2-(2)(4)^2(4)+(4) ?

The solution to (4)^2-(2)(4)^2(4)+(4) is -108

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(4)^2-(2)(4)^2(4)+(4)

(4)^{2} - (2) (4)^{2} (4) + (4)

- 108

Solution steps

(4)^{2} - (2) (4)^{2} (4) + (4)

Follow the PEMDAS order of operations

Calculate exponents

(4)^{2} : 16

(4)^{2}

(4)^{2} = 16

= 16

= 16 - (2) (4)^{2} (4) + (4)

Calculate exponents

(4)^{2} : 16

(4)^{2}

(4)^{2} = 16

= 16

= 16 - (2) \cdot 16 (4) + (4)

Multiply and divide (left to right)

(2) \cdot 16 (4) : 128

(2) \cdot 16 (4)

(2) 16 = 32

(2) \cdot 16

Apply rule:

(a) = a

(2) = 2

= 2 \cdot 16

Multiply the numbers:

2 \cdot 16 = 32

= 32

= 32 (4)

32 (4) = 128

32 (4)

Apply rule:

(a) = a

(4) = 4

= 32 \cdot 4

Multiply the numbers:

32 \cdot 4 = 128

= 128

= 128

= 16 - 128 + (4)

Add and subtract (left to right)

16 - 128 + (4) : - 108

16 - 128 + (4)

16 - 128 = - 112

= - 112 + (4)

- 112 + (4) = - 108

= - 108

= - 108

23 - 12 + 3 - 7

\frac{4}{3} (5)^{3}

6 (- 3)^{2}

(0)^{2} - 5

4 \cdot 4^{5}