What is (4)^2-(2)(4)^2(4)+(4) ?

The solution to (4)^2-(2)(4)^2(4)+(4) is -108

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(4)^2-(2)(4)^2(4)+(4)

(4)^{2} - (2) (4)^{2} (4) + (4)

- 108

Solution steps

(4)^{2} - (2) (4)^{2} (4) + (4)

Follow the PEMDAS order of operations

Calculate exponents

(4)^{2} : 16

= 16 - (2) (4)^{2} (4) + (4)

Calculate exponents

(4)^{2} : 16

= 16 - (2) \cdot 16 (4) + (4)

Multiply and divide (left to right)

(2) \cdot 16 (4) : 128

= 16 - 128 + (4)

Add and subtract (left to right)

16 - 128 + (4) : - 108

= - 108

23 - 12 + 3 - 7

\frac{4}{3} (5)^{3}

6 (- 3)^{2}

(0)^{2} - 5

4 \cdot 4^{5}