What is 2^6*2^2\div 9^2 ?

The solution to 2^6*2^2\div 9^2 is 3 13/81

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2^6*2^2\div 9^2

2^{6} \cdot 2^{2} \div 9^{2}

3 \frac{13}{81}

Solution steps

2^{6} \cdot 2^{2} \div 9^{2}

Follow the PEMDAS order of operations

Calculate exponents

2^{6} : 64

= 64 \cdot 2^{2} \div 9^{2}

Calculate exponents

2^{2} : 4

= 64 \cdot 4 \div 9^{2}

Calculate exponents

9^{2} : 81

= 64 \cdot 4 \div 81

Multiply and divide (left to right)

64 \cdot 4 \div 81 : \frac{256}{81}

= \frac{256}{81}

Convert improper fractions to mixed numbers:

\frac{256}{81} = 3 \frac{13}{81}

= 3 \frac{13}{81}

- [- 11 + (- 5 - 6)] \times (- 4)

(104 + 4 \cdot 2) + 19 - 109 + 56 \div 7

16 \div 2 + 2

\frac{1}{2} \cdot 2^{1} - 4

\frac{1}{2} (1) - 1