What is -3(-1)^3-4(-2)^2 ?

The solution to -3(-1)^3-4(-2)^2 is -13

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-3(-1)^3-4(-2)^2

- 3 (- 1)^{3} - 4 (- 2)^{2}

- 13

Solution steps

- 3 (- 1)^{3} - 4 (- 2)^{2}

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{3} : - 1

(- 1)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 1)^{3} = - 1^{3} = - 1

= - 1

= - 3 (- 1) - 4 (- 2)^{2}

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= - 3 (- 1) - 4 \cdot 4

Multiply and divide (left to right)

- 3 (- 1) : 3

- 3 (- 1)

Apply rule

- a \cdot (- b) = a \cdot b

- 3 (- 1) = 3 \cdot 1 = 3

= 3

= 3 - 4 \cdot 4

Multiply and divide (left to right)

4 \cdot 4 : 16

4 \cdot 4

4 \cdot 4 = 16

= 16

= 3 - 16

Add and subtract (left to right)

3 - 16 : - 13

3 - 16

3 - 16 = - 13

= - 13

= - 13

- 4 {5 + 2 [5 + (- 8)]}

(- 3) \times 3 \times (- 3) \times (- 3) \times 3

9 - 15 + 4

3 \times (2 \times 4^{3}) \div 4

1 - 2 - 3 - 5 + 6 - 7 + 10 + 11 - 13