What is -1/3 (-1)-3 ?

The solution to -1/3 (-1)-3 is -8/3

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-1/3 (-1)-3

- \frac{1}{3} (- 1) - 3

- \frac{8}{3}

Solution steps

- \frac{1}{3} (- 1) - 3

Follow the PEMDAS order of operations

Multiply and divide (left to right)

- \frac{1}{3} (- 1) : \frac{1}{3}

- \frac{1}{3} (- 1)

Apply rule

- a \cdot (- b) = a \cdot b

- \frac{1}{3} (- 1) = \frac{1}{3} \cdot 1 = \frac{1}{3}

= \frac{1}{3}

= \frac{1}{3} - 3

Add and subtract (left to right)

\frac{1}{3} - 3 : - \frac{8}{3}

\frac{1}{3} - 3

\frac{1}{3} - 3 = - \frac{8}{3}

\frac{1}{3} - 3

Convert element to fraction:

3 = \frac{3 \cdot 3}{3}

= - \frac{3 \cdot 3}{3} + \frac{1}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 3 \cdot 3 + 1}{3}

- 3 \cdot 3 + 1 = - 8

- 3 \cdot 3 + 1

Multiply the numbers:

3 \cdot 3 = 9

= - 9 + 1

Add/Subtract the numbers:

- 9 + 1 = - 8

= - 8

= \frac{- 8}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{8}{3}

= - \frac{8}{3}

= - \frac{8}{3}

3^{2} + 1 - 3 - 3

2^{2} \cdot (- 9) - 9

90 - 81 + 27 + 36 - 18 - 9 - 45

2 (6)^{2} - 5

\frac{[ ( 7 - 3 ) ^{2} - 4 ] ^{2}}{9 - 16 \div 8 - 4}