What is 440-[30+6(19-12)] ?

The solution to 440-[30+6(19-12)] is 368

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440-[30+6(19-12)]

440 - [30 + 6 (19 - 12)]

368

Solution steps

440 - [30 + 6 (19 - 12)]

Follow the PEMDAS order of operations

Calculate within parentheses

[30 + 6 (19 - 12)] : 72

30 + 6 (19 - 12)

Calculate within parentheses

(19 - 12) : 7

19 - 12

19 - 12 = 7

= 7

= 30 + 6 \cdot 7

Multiply and divide (left to right)

6 \cdot 7 : 42

6 \cdot 7

6 \cdot 7 = 42

= 42

= 30 + 42

Add and subtract (left to right)

30 + 42 : 72

30 + 42

30 + 42 = 72

= 72

= 72

= 440 - 72

Add and subtract (left to right)

440 - 72 : 368

440 - 72

440 - 72 = 368

= 368

= 368

- 2 (0)^{2}

2 (3)^{1}

1 9^{2} - 1 1^{2}

3/4 + 7/6 - 2/3

3 \times 2^{2}