What is (-2)^4-2(-2)^2-8 ?

The solution to (-2)^4-2(-2)^2-8 is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(-2)^4-2(-2)^2-8

(- 2)^{4} - 2 (- 2)^{2} - 8

0

Solution steps

(- 2)^{4} - 2 (- 2)^{2} - 8

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{4} : 16

(- 2)^{4}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{4} = 2^{4} = 16

= 16

= 16 - 2 (- 2)^{2} - 8

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 16 - 2 \cdot 4 - 8

Multiply and divide (left to right)

2 \cdot 4 : 8

2 \cdot 4

2 \cdot 4 = 8

= 8

= 16 - 8 - 8

Add and subtract (left to right)

16 - 8 - 8 : 0

16 - 8 - 8

16 - 8 = 8

= 8 - 8

8 - 8 = 0

= 0

= 0

1^{3} + 3

(+ 3) - (- 5) - (+ 2) + (+ 7)

- 9 + (- 81) \div (- 3)

8 + (10 - 15 \div 3) + 3 \cdot 4 - 6

- 3 - 3 \times \frac{11}{3}