What is (-2)^4+5-(12-14\div 2)^2 ?

The solution to (-2)^4+5-(12-14\div 2)^2 is -4

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(-2)^4+5-(12-14\div 2)^2

(- 2)^{4} + 5 - (12 - 14 \div 2)^{2}

- 4

Solution steps

(- 2)^{4} + 5 - (12 - 14 \div 2)^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(12 - 14 \div 2) : 5

12 - 14 \div 2

Multiply and divide (left to right)

14 \div 2 : 7

14 \div 2

14 \div 2 = 7

= 7

= 12 - 7

Add and subtract (left to right)

12 - 7 : 5

12 - 7

12 - 7 = 5

= 5

= 5

= (- 2)^{4} + 5 - 5^{2}

Calculate exponents

(- 2)^{4} : 16

(- 2)^{4}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{4} = 2^{4} = 16

= 16

= 16 + 5 - 5^{2}

Calculate exponents

5^{2} : 25

5^{2}

5^{2} = 25

= 25

= 16 + 5 - 25

Add and subtract (left to right)

16 + 5 - 25 : - 4

16 + 5 - 25

16 + 5 = 21

= 21 - 25

21 - 25 = - 4

= - 4

= - 4

7 \cdot (15 \div 3 + 5)

- 6 - 3 - 2

- {(- 5) + 3 + (- 4)} + 2

4 (5 - 2)^{3} - 45 \div 3 + 7

6 \div 2 (1)

What is (-2)^4+5-(12-14\div 2)^2 ?
The solution to (-2)^4+5-(12-14\div 2)^2 is -4