What is -(3)^2+3(3) ?

The solution to -(3)^2+3(3) is 0

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-(3)^2+3(3)

- (3)^{2} + 3 (3)

0

Solution steps

- (3)^{2} + 3 (3)

Follow the PEMDAS order of operations

Calculate exponents

(3)^{2} : 9

(3)^{2}

(3)^{2} = 9

= 9

= - 9 + 3 (3)

Multiply and divide (left to right)

3 (3) : 9

3 (3)

Apply rule:

(a) = a

(3) = 3

= 3 \cdot 3

Multiply the numbers:

3 \cdot 3 = 9

= 9

= - 9 + 9

Add and subtract (left to right)

- 9 + 9 : 0

- 9 + 9

- 9 + 9 = 0

= 0

= 0

3 (- 1)^{2} + 5 - 2

- 1^{2} + 2 (- 1) + 4

3 \div 7 + 5 \div 14 - 3 \div 49 + 1 \div 4 - 7 \div 2

10 \div 5 \times 4 + 5 + 5 - 6

(4 - 11) \times (12 - 18)