The solution to 1/4 (-8)+2 is 0

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1/4 (-8)+2

Solution

\frac{1}{4} (- 8) + 2

0

Solution steps

\frac{1}{4} (- 8) + 2

Follow the PEMDAS order of operations

Multiply and divide (left to right)

\frac{1}{4} (- 8) : - 2

\frac{1}{4} (- 8)

Apply rule

a \cdot (- b) = - a \cdot b

\frac{1}{4} (- 8) = - \frac{1}{4} \cdot 8

Convert element to fraction:

8 = \frac{8}{1}

= - \frac{1}{4} \cdot \frac{8}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{1}{4} \cdot \frac{8}{1} = \frac{1 \cdot 8}{4 \cdot 1}

= - \frac{1 \cdot 8}{4 \cdot 1}

\frac{1 \cdot 8}{4 \cdot 1} = 2

\frac{1 \cdot 8}{4 \cdot 1}

\frac{1 \cdot 8}{4 \cdot 1} = \frac{8}{4}

\frac{1 \cdot 8}{4 \cdot 1}

Multiply the numbers:

1 \cdot 8 = 8

= \frac{8}{4 \cdot 1}

Multiply the numbers:

4 \cdot 1 = 4

= \frac{8}{4}

= \frac{8}{4}

Divide the numbers:

\frac{8}{4} = 2

= 2

= - 2

= - 2 + 2

Add and subtract (left to right)

- 2 + 2 : 0

- 2 + 2

- 2 + 2 = 0

= 0

= 0

9 \div 3 + 7 + (20 - 13)

2 \times 12 + 1 3^{2}

2 \div (- \frac{1}{4} + 1)

12 + (- 12) + (- 18) + (- 19) + (- 15)

3 \times (- 1 - (- 5))