What is 5-(-2)^2-2(-2)-2 ?

The solution to 5-(-2)^2-2(-2)-2 is 3

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5-(-2)^2-2(-2)-2

5 - (- 2)^{2} - 2 (- 2) - 2

3

Solution steps

5 - (- 2)^{2} - 2 (- 2) - 2

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 5 - 4 - 2 (- 2) - 2

Multiply and divide (left to right)

2 (- 2) : - 4

2 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 2) = - 2 \cdot 2 = - 4

= - 4

= 5 - 4 - (- 4) - 2

Add and subtract (left to right)

5 - 4 - (- 4) - 2 : 3

5 - 4 - (- 4) - 2

5 - 4 = 1

= 1 - (- 4) - 2

Apply rule

- (- a) = + a

- (- 4) = + 4

= 1 + 4 - 2

1 + 4 = 5

= 5 - 2

5 - 2 = 3

= 3

= 3

- 1 + (- 6) - (- 4) - 3

- 36 + 69 + (- 17) + (- 42) + 32

6 (- 1) - 10

2 \times (- 5) \times + 9

\frac{- 3 ( 9 - 13 ) ^{2}}{6 \cdot 2}