What is -1/3+(-3)-2 ?

The solution to -1/3+(-3)-2 is -16/3

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-1/3+(-3)-2

- \frac{1}{3} + (- 3) - 2

- \frac{16}{3}

Solution steps

- \frac{1}{3} + (- 3) - 2

Follow the PEMDAS order of operations

Add and subtract (left to right)

Apply rule

+ (- a) = - a

+ (- 3) = - 3

= - \frac{1}{3} - 3 - 2

- \frac{1}{3} - 3 = - \frac{10}{3}

- \frac{1}{3} - 3

Convert element to fraction:

3 = \frac{3 \cdot 3}{3}

= - \frac{3 \cdot 3}{3} - \frac{1}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 3 \cdot 3 - 1}{3}

- 3 \cdot 3 - 1 = - 10

- 3 \cdot 3 - 1

Multiply the numbers:

3 \cdot 3 = 9

= - 9 - 1

Subtract the numbers:

- 9 - 1 = - 10

= - 10

= \frac{- 10}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{10}{3}

= - \frac{10}{3} - 2

- \frac{10}{3} - 2 = - \frac{16}{3}

- \frac{10}{3} - 2

Convert element to fraction:

2 = \frac{2 \cdot 3}{3}

= - \frac{2 \cdot 3}{3} - \frac{10}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 2 \cdot 3 - 10}{3}

- 2 \cdot 3 - 10 = - 16

- 2 \cdot 3 - 10

Multiply the numbers:

2 \cdot 3 = 6

= - 6 - 10

Subtract the numbers:

- 6 - 10 = - 16

= - 16

= \frac{- 16}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{16}{3}

= - \frac{16}{3}

3 + 4 (2 - 3) + 8

3 (12 - 2 (3))^{2}

(3) + (- 8) - (- 3)

16 + 40 - 8 - 24 + 72 - 64

3 - (- 2)^{2}