What is 4+[ 3/2+4/8 ]-6 ?

The solution to 4+[ 3/2+4/8 ]-6 is 0

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4+[ 3/2+4/8 ]-6

4 + [\frac{3}{2} + \frac{4}{8}] - 6

0

Solution steps

4 + [\frac{3}{2} + \frac{4}{8}] - 6

\frac{4}{8} = \frac{1}{2}

Cancel the common factor:

4

\frac{1}{2}

= 4 + [\frac{3}{2} + \frac{1}{2}] - 6

Follow the PEMDAS order of operations

Calculate within parentheses

[\frac{3}{2} + \frac{1}{2}] : 2

\frac{3}{2} + \frac{1}{2}

\frac{3}{2} + \frac{1}{2} = 2

\frac{3}{2} + \frac{1}{2}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 + 1}{2}

Add the numbers:

3 + 1 = 4

= \frac{4}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2

= 2

= 4 + 2 - 6

Add and subtract (left to right)

4 + 2 - 6 : 0

4 + 2 - 6

4 + 2 = 6

= 6 - 6

6 - 6 = 0

= 0

= 0

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