What is (1/2-1/3)-1/6 ?

The solution to (1/2-1/3)-1/6 is 0

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(1/2-1/3)-1/6

(\frac{1}{2} - \frac{1}{3}) - \frac{1}{6}

0

Solution steps

(\frac{1}{2} - \frac{1}{3}) - \frac{1}{6}

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{1}{2} - \frac{1}{3}) : \frac{1}{6}

\frac{1}{2} - \frac{1}{3}

\frac{1}{2} - \frac{1}{3} = \frac{1}{6}

\frac{1}{2} - \frac{1}{3}

Least Common Multiplier of

2, 3 : 6

2, 3

Least Common Multiplier (LCM)

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Prime factorization of

3 : 3

3

3

is a prime number, therefore no factorization is possible

= 3

Multiply each factor the greatest number of times it occurs in either

2

3

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

6

For

\frac{1}{2} :

multiply the denominator and numerator by

3

\frac{1}{2} = \frac{1 \cdot 3}{2 \cdot 3} = \frac{3}{6}

For

\frac{1}{3} :

multiply the denominator and numerator by

2

\frac{1}{3} = \frac{1 \cdot 2}{3 \cdot 2} = \frac{2}{6}

= \frac{3}{6} - \frac{2}{6}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 - 2}{6}

Subtract the numbers:

3 - 2 = 1

= \frac{1}{6}

= \frac{1}{6}

= \frac{1}{6} - \frac{1}{6}

Add and subtract (left to right)

\frac{1}{6} - \frac{1}{6} : 0

\frac{1}{6} - \frac{1}{6}

\frac{1}{6} - \frac{1}{6} = 0

= 0

= 0

- 2^{2} + 2 - 2

51 (90) + 100 (10)

16 (1)^{3}

- 1/3 + 4/9 + (2/3) - 3 + 8/6

3 + (- (6 + 15) - (5 + 14)) + (4 + 5)