What is -(-2)^2+6(-2)+1 ?

The solution to -(-2)^2+6(-2)+1 is -15

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-(-2)^2+6(-2)+1

- (- 2)^{2} + 6 (- 2) + 1

- 15

Solution steps

- (- 2)^{2} + 6 (- 2) + 1

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= - 4 + 6 (- 2) + 1

Multiply and divide (left to right)

6 (- 2) : - 12

6 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

6 (- 2) = - 6 \cdot 2 = - 12

= - 12

= - 4 - 12 + 1

Add and subtract (left to right)

- 4 - 12 + 1 : - 15

- 4 - 12 + 1

- 4 - 12 = - 16

= - 16 + 1

- 16 + 1 = - 15

= - 15

= - 15

- 4 + {- 3 + [- 3 + 8 + (- 3 + (- 8))]}

(3 \div 4) \times 2

- (- 1^{2}) - 4 + 5

10 - 2^{3}

10 - 2^{2}