What is (-4)^2+4(-4)+3 ?

The solution to (-4)^2+4(-4)+3 is 3

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(-4)^2+4(-4)+3

(- 4)^{2} + 4 (- 4) + 3

3

Solution steps

(- 4)^{2} + 4 (- 4) + 3

Follow the PEMDAS order of operations

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= 16 + 4 (- 4) + 3

Multiply and divide (left to right)

4 (- 4) : - 16

4 (- 4)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 4) = - 4 \cdot 4 = - 16

= - 16

= 16 - 16 + 3

Add and subtract (left to right)

16 - 16 + 3 : 3

16 - 16 + 3

16 - 16 = 0

= 0 + 3

0 + 3 = 3

= 3

= 3

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8^{3} + 20 - 3^{2}