What is 8^3+(-5)^2+4^1+4^0+5 ?

The solution to 8^3+(-5)^2+4^1+4^0+5 is 547

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8^3+(-5)^2+4^1+4^0+5

8^{3} + (- 5)^{2} + 4^{1} + 4^{0} + 5

547

Solution steps

8^{3} + (- 5)^{2} + 4^{1} + 4^{0} + 5

Follow the PEMDAS order of operations

Calculate exponents

8^{3} : 512

8^{3}

8^{3} = 512

= 512

= 512 + (- 5)^{2} + 4^{1} + 4^{0} + 5

Calculate exponents

(- 5)^{2} : 25

(- 5)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 5)^{2} = 5^{2} = 25

= 25

= 512 + 25 + 4^{1} + 4^{0} + 5

Calculate exponents

4^{1} : 4

4^{1}

4^{1} = 4

= 4

= 512 + 25 + 4 + 4^{0} + 5

Calculate exponents

4^{0} : 1

4^{0}

4^{0} = 1

= 1

= 512 + 25 + 4 + 1 + 5

Add and subtract (left to right)

512 + 25 + 4 + 1 + 5 : 547

512 + 25 + 4 + 1 + 5

512 + 25 = 537

= 537 + 4 + 1 + 5

537 + 4 = 541

= 541 + 1 + 5

541 + 1 = 542

= 542 + 5

542 + 5 = 547

= 547

= 547

- 3 (2)^{2} + 6 (2) + 5

((- 8) + (- 12) \div (4)) \times (- 1) - ((- 34) + 31)

1000 \div (- 5) \div (- 25) \div (+ 3)

28 + 2^{6} \div 16

- (- 3)^{2} + 8 (- 3) - 8