What is [(8\div 2+6)-4]+[3-2(5)] ?

The solution to [(8\div 2+6)-4]+[3-2(5)] is -1

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[(8\div 2+6)-4]+[3-2(5)]

[(8 \div 2 + 6) - 4] + [3 - 2 (5)]

- 1

Solution steps

[(8 \div 2 + 6) - 4] + [3 - 2 (5)]

Follow the PEMDAS order of operations

Calculate within parentheses

[(8 \div 2 + 6) - 4] : 6

(8 \div 2 + 6) - 4

Calculate within parentheses

(8 \div 2 + 6) : 10

8 \div 2 + 6

Multiply and divide (left to right)

8 \div 2 : 4

8 \div 2

8 \div 2 = 4

= 4

= 4 + 6

Add and subtract (left to right)

4 + 6 : 10

4 + 6

4 + 6 = 10

= 10

= 10

= 10 - 4

Add and subtract (left to right)

10 - 4 : 6

10 - 4

10 - 4 = 6

= 6

= 6

= 6 + [3 - 2 (5)]

Calculate within parentheses

[3 - 2 (5)] : - 7

3 - 2 (5)

Multiply and divide (left to right)

2 (5) : 10

2 (5)

Apply rule:

(a) = a

(5) = 5

= 2 \cdot 5

Multiply the numbers:

2 \cdot 5 = 10

= 10

= 3 - 10

Add and subtract (left to right)

3 - 10 : - 7

3 - 10

3 - 10 = - 7

= - 7

= - 7

= 6 - 7

Add and subtract (left to right)

6 - 7 : - 1

6 - 7

6 - 7 = - 1

= - 1

= - 1

\frac{2 + 0 - 7 - 7 - 5 - 7 - 5 + 1 + 2 - 5}{10}

8 + (- 25) + 16 (- 25) - 16

\frac{6 \cdot ( - 2 + 1 )}{- 2}

- 3 (0 - 2)^{2} + 18

5 \times 5 - 4 \times 5 (12 - 2^{2}) + 2 + 10 \div 2

What is [(8\div 2+6)-4]+[3-2(5)] ?
The solution to [(8\div 2+6)-4]+[3-2(5)] is -1