What is -(-1)^2+2(-1)-1 ?

The solution to -(-1)^2+2(-1)-1 is -4

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-(-1)^2+2(-1)-1

- (- 1)^{2} + 2 (- 1) - 1

- 4

Solution steps

- (- 1)^{2} + 2 (- 1) - 1

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= - 1 + 2 (- 1) - 1

Multiply and divide (left to right)

2 (- 1) : - 2

2 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 1) = - 2 \cdot 1 = - 2

= - 2

= - 1 - 2 - 1

Add and subtract (left to right)

- 1 - 2 - 1 : - 4

- 1 - 2 - 1

- 1 - 2 = - 3

= - 3 - 1

- 3 - 1 = - 4

= - 4

= - 4

18 - (3 \times 4)

- 4 \div (- 2) \times (- 1) + (- 2)

1 0^{3} - 4 \times 1 0^{2}

2144 \div 1 0^{4}

(3)^{4} - 4 (3)^{3} + 5