What is 8\times (2-8)+(-5)^2-(1-7) ?

The solution to 8\times (2-8)+(-5)^2-(1-7) is -17

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8\times (2-8)+(-5)^2-(1-7)

8 \cdot (2 - 8) + (- 5)^{2} - (1 - 7)

- 17

Solution steps

8 (2 - 8) + (- 5)^{2} - (1 - 7)

Follow the PEMDAS order of operations

Calculate within parentheses

(2 - 8) : - 6

2 - 8

2 - 8 = - 6

= - 6

= 8 (- 6) + (- 5)^{2} - (1 - 7)

Calculate within parentheses

(1 - 7) : - 6

1 - 7

1 - 7 = - 6

= - 6

= 8 (- 6) + (- 5)^{2} - (- 6)

Calculate exponents

(- 5)^{2} : 25

(- 5)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 5)^{2} = 5^{2} = 25

= 25

= 8 (- 6) + 25 - (- 6)

Multiply and divide (left to right)

8 (- 6) : - 48

8 (- 6)

Apply rule

a \cdot (- b) = - a \cdot b

8 (- 6) = - 8 \cdot 6 = - 48

= - 48

= - 48 + 25 - (- 6)

Add and subtract (left to right)

- 48 + 25 - (- 6) : - 17

- 48 + 25 - (- 6)

- 48 + 25 = - 23

= - 23 - (- 6)

Apply rule

- (- a) = + a

- (- 6) = + 6

= - 23 + 6

- 23 + 6 = - 17

= - 17

= - 17

(3 \times 5 \times 8 \times 4) \div (3 \times 8)

(3^{3} + 3^{2})^{2}

(8 (10) - 9)^{3}

2^{8} \div 2

8^{2} + 2^{3}

What is 8\times (2-8)+(-5)^2-(1-7) ?
The solution to 8\times (2-8)+(-5)^2-(1-7) is -17