What is 4(3)^2-3(3)+7 ?

The solution to 4(3)^2-3(3)+7 is 34

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4(3)^2-3(3)+7

4 (3)^{2} - 3 (3) + 7

34

Solution steps

4 (3)^{2} - 3 (3) + 7

Follow the PEMDAS order of operations

Calculate exponents

(3)^{2} : 9

(3)^{2}

(3)^{2} = 9

= 9

= 4 \cdot 9 - 3 (3) + 7

Multiply and divide (left to right)

4 \cdot 9 : 36

4 \cdot 9

4 \cdot 9 = 36

= 36

= 36 - 3 (3) + 7

Multiply and divide (left to right)

3 (3) : 9

3 (3)

Apply rule:

(a) = a

(3) = 3

= 3 \cdot 3

Multiply the numbers:

3 \cdot 3 = 9

= 9

= 36 - 9 + 7

Add and subtract (left to right)

36 - 9 + 7 : 34

36 - 9 + 7

36 - 9 = 27

= 27 + 7

27 + 7 = 34

= 34

= 34

\frac{1 ^{2} - 4}{1 - 2}

4 \cdot \frac{1}{2} + 6

- 4 \cdot 2 \cdot (- 3)

2 - 4 - 3

8^{2} - (8 \cdot 2 + 5^{2})