What is ((8-9)^2-2+3)/(52-2\times 4^2) ?

The solution to ((8-9)^2-2+3)/(52-2\times 4^2) is 1/10

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((8-9)^2-2+3)/(52-2\times 4^2)

\frac{( 8 - 9 ) ^{2} - 2 + 3}{52 - 2 \cdot 4 ^{2}}

\frac{1}{10}

Solution steps

\frac{( 8 - 9 ) ^{2} - 2 + 3}{52 - 2 \cdot 4 ^{2}}

Solve

(8 - 9)^{2} - 2 + 3 : 2

Follow the PEMDAS order of operations

Calculate within parentheses

(8 - 9) : - 1

8 - 9

8 - 9 = - 1

= - 1

= (- 1)^{2} - 2 + 3

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 1 - 2 + 3

Add and subtract (left to right)

1 - 2 + 3 : 2

1 - 2 + 3

1 - 2 = - 1

= - 1 + 3

- 1 + 3 = 2

= 2

= 2

Solve

52 - 2 \cdot 4^{2} : 20

Follow the PEMDAS order of operations

Calculate exponents

4^{2} : 16

4^{2}

4^{2} = 16

= 16

= 52 - 2 \cdot 16

Multiply and divide (left to right)

2 \cdot 16 : 32

2 \cdot 16

2 \cdot 16 = 32

= 32

= 52 - 32

Add and subtract (left to right)

52 - 32 : 20

52 - 32

52 - 32 = 20

= 20

= 20

= \frac{2}{20}

Cancel the common factor:

2

= \frac{1}{10}

\frac{3 ( 2 ) ^{4}}{4}

- 20 - 3 + 2 - [- 4 + 5 + 6]

6 \div 5 - 4 \times 10

- 6 (1)^{2} + 8 (1) + 5

- 2 \times (- 5 + 2) + 10 \div (- 2)

What is ((8-9)^2-2+3)/(52-2\times 4^2) ?
The solution to ((8-9)^2-2+3)/(52-2\times 4^2) is 1/10