What is -3/2 \times 3+5 ?

The solution to -3/2 \times 3+5 is 1/2

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-3/2 \times 3+5

- \frac{3}{2} \cdot 3 + 5

\frac{1}{2}

Solution steps

- \frac{3}{2} \cdot 3 + 5

Follow the PEMDAS order of operations

Multiply and divide (left to right)

- \frac{3}{2} \cdot 3 : - \frac{9}{2}

- \frac{3}{2} \cdot 3

Convert element to fraction:

3 = \frac{3}{1}

= - \frac{3}{2} \cdot \frac{3}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{3}{2} \cdot \frac{3}{1} = \frac{3 \cdot 3}{2 \cdot 1}

= - \frac{3 \cdot 3}{2 \cdot 1}

Multiply the numbers:

3 \cdot 3 = 9

= - \frac{9}{2 \cdot 1}

Multiply the numbers:

2 \cdot 1 = 2

= - \frac{9}{2}

= - \frac{9}{2} + 5

Add and subtract (left to right)

- \frac{9}{2} + 5 : \frac{1}{2}

- \frac{9}{2} + 5

- \frac{9}{2} + 5 = \frac{1}{2}

- \frac{9}{2} + 5

Convert element to fraction:

5 = \frac{5 \cdot 2}{2}

= \frac{5 \cdot 2}{2} - \frac{9}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{5 \cdot 2 - 9}{2}

5 \cdot 2 - 9 = 1

5 \cdot 2 - 9

Multiply the numbers:

5 \cdot 2 = 10

= 10 - 9

Subtract the numbers:

10 - 9 = 1

= 1

= \frac{1}{2}

= \frac{1}{2}

= \frac{1}{2}

(9 - 3) \times 2 + 3 \div (5 - 2)

\frac{3 ^{2} \cdot 5 ^{0}}{2 ^{3}}

4 + [[(5 \times 2) - 12] \div 2]

4 (2 + 3 - 1) - 12

5 - 16/8 + 3 + 8/5