What is 2(-4)^2+8(-4)-4 ?

The solution to 2(-4)^2+8(-4)-4 is -4

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2(-4)^2+8(-4)-4

2 (- 4)^{2} + 8 (- 4) - 4

- 4

Solution steps

2 (- 4)^{2} + 8 (- 4) - 4

Follow the PEMDAS order of operations

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= 2 \cdot 16 + 8 (- 4) - 4

Multiply and divide (left to right)

2 \cdot 16 : 32

2 \cdot 16

2 \cdot 16 = 32

= 32

= 32 + 8 (- 4) - 4

Multiply and divide (left to right)

8 (- 4) : - 32

8 (- 4)

Apply rule

a \cdot (- b) = - a \cdot b

8 (- 4) = - 8 \cdot 4 = - 32

= - 32

= 32 - 32 - 4

Add and subtract (left to right)

32 - 32 - 4 : - 4

32 - 32 - 4

32 - 32 = 0

= 0 - 4

0 - 4 = - 4

= - 4

= - 4

(\frac{1}{2}) (2 - 3)

1 5^{2} + 3 7^{2}

6 + 2 \times 3 - (9 - 4)

+ (- 30) + (15) + (- 17) + (- 12) + (17)

2 + 3 \times 8 - 18 \div 6 - 7