What is ((2-2^2)^3)/2 ?

The solution to ((2-2^2)^3)/2 is -4

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((2-2^2)^3)/2

\frac{( 2 - 2 ^{2} ) ^{3}}{2}

- 4

Solution steps

\frac{( 2 - 2 ^{2} ) ^{3}}{2}

Solve

(2 - 2^{2})^{3} : - 8

Follow the PEMDAS order of operations

Calculate within parentheses

(2 - 2^{2}) : - 2

2 - 2^{2}

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= 2 - 4

Add and subtract (left to right)

2 - 4 : - 2

2 - 4

2 - 4 = - 2

= - 2

= - 2

= (- 2)^{3}

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= - 8

= \frac{- 8}{2}

Simplify

\frac{- 8}{2} : - 4

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{8}{2}

Divide the numbers:

\frac{8}{2} = 4

= - 4

= - 4

8^{2} \cdot 6

3 (3)^{2} - 6 (3) - 9

2 - 3 \times 5

(- 4) + (- 1) - (- 1) + (- 3)

- 2 (1 - 5)