What is 2(0)^2+6(1)-5 ?

The solution to 2(0)^2+6(1)-5 is 1

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2(0)^2+6(1)-5

2 (0)^{2} + 6 (1) - 5

1

Solution steps

2 (0)^{2} + 6 (1) - 5

Follow the PEMDAS order of operations

Calculate exponents

(0)^{2} : 0

(0)^{2}

(0)^{2} = 0

= 0

= 2 \cdot 0 + 6 (1) - 5

Multiply and divide (left to right)

2 \cdot 0 : 0

2 \cdot 0

2 \cdot 0 = 0

= 0

= 0 + 6 (1) - 5

Multiply and divide (left to right)

6 (1) : 6

6 (1)

Apply rule:

(a) = a

(1) = 1

= 6 \cdot 1

Multiply the numbers:

6 \cdot 1 = 6

= 6

= 0 + 6 - 5

Add and subtract (left to right)

0 + 6 - 5 : 1

0 + 6 - 5

0 + 6 = 6

= 6 - 5

6 - 5 = 1

= 1

= 1

- 4 \times 3 \div 6 + (- 2)

(10 + 24 \div 6) \div 7 + 3 \times (4 \times 4 - 4)

1 + 9 \div 3 \cdot 2

(8 \times 6 + 2) \times 9 - 5 \times 3

51 \times 1 - 1