What is 2*5-3*3^2+5*(2^3)/4 ?

The solution to 2*5-3*3^2+5*(2^3)/4 is -7

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simplify 25-33^2+5*(2^3)/4

simplify

2 \cdot 5 - 3 \cdot 3^{2} + 5 \cdot \frac{2 ^{3}}{4}

- 7

Solution steps

2 \cdot 5 - 3 \cdot 3^{2} + 5 \cdot \frac{2 ^{3}}{4}

2 \cdot 5 = 10

2 \cdot 5

Multiply the numbers:

2 \cdot 5 = 10

= 10

3 \cdot 3^{2} = 27

3 \cdot 3^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

3 \cdot 3^{2} = 3^{1 + 2}

= 3^{1 + 2}

Add the numbers:

1 + 2 = 3

= 3^{3}

3^{3} = 27

= 27

5 \cdot \frac{2 ^{3}}{4} = 10

5 \cdot \frac{2 ^{3}}{4}

Cancel

\frac{2 ^{3}}{4} : 2

\frac{2 ^{3}}{4}

Factor the number:

4 = 2^{2}

= \frac{2 ^{3}}{2 ^{2}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

= 2^{3 - 2}

Subtract the numbers:

3 - 2 = 1

= 2^{1}

Apply exponent rule:

a^{1} = a

= 2

= 5 \cdot 2

Multiply the numbers:

5 \cdot 2 = 10

= 10

= 10 - 27 + 10

Add the numbers:

10 - 27 + 10 = - 7

= - 7

2 + 2 \cdot (6 + 6^{2}) + 6^{3}

\frac{10}{5} + 10 - 9 \cdot 11

\frac{0.05}{2}

4 - 4 \cdot 7 + 3

2.3