What is -(1)^2-(-1)^3+(-1)^5 ?

The solution to -(1)^2-(-1)^3+(-1)^5 is -1

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-(1)^2-(-1)^3+(-1)^5

- (1)^{2} - (- 1)^{3} + (- 1)^{5}

- 1

Solution steps

- (1)^{2} - (- 1)^{3} + (- 1)^{5}

Follow the PEMDAS order of operations

Calculate exponents

(1)^{2} : 1

(1)^{2}

(1)^{2} = 1

= 1

= - 1 - (- 1)^{3} + (- 1)^{5}

Calculate exponents

(- 1)^{3} : - 1

(- 1)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 1)^{3} = - 1^{3} = - 1

= - 1

= - 1 - (- 1) + (- 1)^{5}

Calculate exponents

(- 1)^{5} : - 1

(- 1)^{5}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 1)^{5} = - 1^{5} = - 1

= - 1

= - 1 - (- 1) - 1

Add and subtract (left to right)

- 1 - (- 1) - 1 : - 1

- 1 - (- 1) - 1

Apply rule

- (- a) = + a

- (- 1) = + 1

= - 1 + 1 - 1

- 1 + 1 = 0

= 0 - 1

0 - 1 = - 1

= - 1

= - 1

9 (\frac{3}{3})^{2} - 6 (\frac{3}{3})

- 2 (9) - 1

4^{2} + 2^{2} - 4 \cdot 6 \div 3 \cdot 2

- 38 + (- 40) - (- 18)

125 + 15 - 2