What is -4+(-8+4)^3+6-3^2+4 ?

The solution to -4+(-8+4)^3+6-3^2+4 is -67

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-4+(-8+4)^3+6-3^2+4

- 4 + (- 8 + 4)^{3} + 6 - 3^{2} + 4

- 67

Solution steps

- 4 + (- 8 + 4)^{3} + 6 - 3^{2} + 4

Follow the PEMDAS order of operations

Calculate within parentheses

(- 8 + 4) : - 4

- 8 + 4

- 8 + 4 = - 4

= - 4

= - 4 + (- 4)^{3} + 6 - 3^{2} + 4

Calculate exponents

(- 4)^{3} : - 64

(- 4)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 4)^{3} = - 4^{3} = - 64

= - 64

= - 4 - 64 + 6 - 3^{2} + 4

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= - 4 - 64 + 6 - 3^{2} + 4

Add and subtract (left to right)

- 4 - 64 + 6 - 3^{2} + 4 : - 67

- 4 - 64 + 6 - 3^{2} + 4

- 4 - 64 = - 68

= - 68 + 6 - 3^{2} + 4

- 68 + 6 = - 62

= - 62 - 3^{2} + 4

- 62 - 3^{2} = - 71

= - 71 + 4

- 71 + 4 = - 67

= - 67

= - 67

8 \times (1 \div 8)

6 (0) - 3 (- 3)

3 \times (9 - 2 \times 3)^{2} + 5 \times 2

5/6 \times 1/2

336 - 186 - 70