What is (2)^2-5(2)-10+15 ?

The solution to (2)^2-5(2)-10+15 is -1

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(2)^2-5(2)-10+15

(2)^{2} - 5 (2) - 10 + 15

- 1

Solution steps

(2)^{2} - 5 (2) - 10 + 15

Follow the PEMDAS order of operations

Calculate exponents

(2)^{2} : 4

(2)^{2}

(2)^{2} = 4

= 4

= 4 - 5 (2) - 10 + 15

Multiply and divide (left to right)

5 (2) : 10

5 (2)

Apply rule:

(a) = a

(2) = 2

= 5 \cdot 2

Multiply the numbers:

5 \cdot 2 = 10

= 10

= 4 - 10 - 10 + 15

Add and subtract (left to right)

4 - 10 - 10 + 15 : - 1

4 - 10 - 10 + 15

4 - 10 = - 6

= - 6 - 10 + 15

- 6 - 10 = - 16

= - 16 + 15

- 16 + 15 = - 1

= - 1

= - 1

2 \times (5 - 3 + 21 \div 3)^{2}

25 \cdot 12 \cdot (- 4)

(18 - 9) \times 4 + 8 + 35 - 5

1 0^{2} \div (49 - 59) + 1 \div 1 0^{2}

\frac{( - 7 ) ^{7}}{( - 7 ) ^{4}}