What is (3-7)^2-(-6)-2 ?

The solution to (3-7)^2-(-6)-2 is 20

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(3-7)^2-(-6)-2

(3 - 7)^{2} - (- 6) - 2

20

Solution steps

(3 - 7)^{2} - (- 6) - 2

Follow the PEMDAS order of operations

Calculate within parentheses

(3 - 7) : - 4

3 - 7

3 - 7 = - 4

= - 4

= (- 4)^{2} - (- 6) - 2

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= 16 - (- 6) - 2

Add and subtract (left to right)

16 - (- 6) - 2 : 20

16 - (- 6) - 2

Apply rule

- (- a) = + a

- (- 6) = + 6

= 16 + 6 - 2

16 + 6 = 22

= 22 - 2

22 - 2 = 20

= 20

= 20

36 \times 3 - 8 \times (- 6^{2})

7 - 5^{2} + 2

3 (- 1)^{3} - (- 1)^{2}

3 \times 2 + 3 - (- 5)

5 \cdot 2^{4} \div 4